If a solution contains 9 mg of salt per 1000 mL, how many mg of salt are needed for 250 mL?

Prepare for the NLN PAX Mathematics 1 Exam. Study with flashcards and multiple-choice questions, complete with explanations and hints. Boost your confidence and get ready for your exam!

Multiple Choice

If a solution contains 9 mg of salt per 1000 mL, how many mg of salt are needed for 250 mL?

Explanation:
This question tests proportionality and how to scale a given quantity to a different volume. If you have 9 mg of salt in 1000 mL, the amount per mL is 9/1000 = 0.009 mg/mL. For 250 mL, multiply: 0.009 × 250 = 2.25 mg. Another quick way is to note that 250 mL is a quarter of 1000 mL, so the amount is a quarter of 9 mg, which is 9 ÷ 4 = 2.25 mg. So 2.25 mg of salt are needed.

This question tests proportionality and how to scale a given quantity to a different volume. If you have 9 mg of salt in 1000 mL, the amount per mL is 9/1000 = 0.009 mg/mL. For 250 mL, multiply: 0.009 × 250 = 2.25 mg. Another quick way is to note that 250 mL is a quarter of 1000 mL, so the amount is a quarter of 9 mg, which is 9 ÷ 4 = 2.25 mg. So 2.25 mg of salt are needed.

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